# Circuit with Two Diodes

1. The problem statement, all variables and given/known data
Compute V3(t)-V4(t). The capacitors are initially discharged, the voltage source is turned on at t = 0, and the diodes forward voltage drop is negligible (Vf = 0). What is the value of V3(10s)  V4(10s)?

Vi=4sin(2∏t)
RC= 0.1s 2. Relevant equations
i (over capacitor) = CdV/dt
i (over resistor) = V/R
Assume Diode is either on (id>0) or off (id=0)

3. The attempt at a solution

I used the node method: node above the top capacitor has voltage V1 and node above the bottom capacitor has voltage V2. Using KCL at those two nodes, I found id1=(CdV1/dt)+(V3/R) and id2=-(CdV2/dt)-(V4/R). Unknowns are id1, id2, V1, V2, V3, and V4.

Based on whether I assume a diode is on/off I can assume V1=Vi or V2=Vi and that id1=0 or id2=0, so that eliminates two unknowns. I’m still left with 4 variables though and can’t see any other equations to solve for them. I was thinking use the node between the two diodes and the voltage source, but I don’t know the current coming off the source. And there aren’t any closed loops for me to use KVL.
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

http://ift.tt/1hnhT4U