Centripetal forces

1. The problem statement, all variables and given/known data

A 1.5 kg mass tied to the roof rotates with constant speed in a horizontal
circle. The string makes an angle of 30 deg to the vertical.

a) determine the velocity , the centripetal acceleration and the centripetal
force on the mass.

b) determine the tension in the string.

c) say the mass is given a push so that now the mass rotates with a constant
velocity of 9.4 m/s . Determine the angle the string makes with the vertical
, the centripetal force on the mass and the tension in the string.

2. Relevant equations

∑Fradial = TsinΘ = mv2/R

∑Fy = TcosΘ – mg = 0

3. The attempt at a solution

To solve part a:

First I found my R by,

R = LsinΘ = 1.5sin30° = .75m

Second my T by,

T= mg/cosΘ = 1.5*9.8/cos30° = 16.97 N

Now I find my velocity by,

V= sqrt((R*T*sinΘ)/m)) = sqrt((.75*16.97*sin30°)/1.5) = 2.06 m/s

the centripetal acceleration,

v2/R = a

a = TsinΘ/m = 16.97*sin30°/1.5 = 5.66 m/s2

for part b I already found my tension to be 17N.

Part C is where I am having trouble, how can i find the angle Θ with the new constant velocity if im not given a radius or tension?

http://ift.tt/1fDZT1j

Leave a comment

Your email address will not be published.


*


Show Buttons
Hide Buttons