Calculating work done on nonlinear spring

Can anyone help me solve this problem? It seemed straightforward at first, but I am not getting the correct answer of -12 Nm. Thank you!!

A nonlinear spring is modeled by a force law given by F(x) = -10x + 3x^2, where F is measured in newtons and x in meters. How much work is done stretching the spring to x = +2.0 m from its equilibrium position at x = 0.0 m?

2. Attempt: W = F*d; F = -8N, so -8N * 2m = -16J

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