**1. The problem statement, all variables and given/known data**

A block of mass 2kg, moving at velocity 2.68 m/s, slides across a rough 3m surface with a coefficient of kinetic friction of .4. Calculate the energy lost to the 3m rough surface.

M=2kg

uK=.4

V=2.68 m/s

D=3m

**2. Relevant equations**

1/2mv^2

uK*Fn*D

**3. The attempt at a solution**

I used the kinetic energy equation of 1/2mv^2 to get 7.18J. Then I did uK*Fn*D to get 24J, where Fn is normal force and Gravity = 10m/s^2. I have no idea where to go from here.

http://ift.tt/1rJpJJY