# Bouyant force plastic tube

**1. The problem statement, all variables and given/known data**

A plastic tube has a cross-sectional area of 5.00 cm^2. The tube is shaped sort of like a "U". The left arm is filled with water until the right arm of length 0.800 m is full of water. The right arm is then sealed with a cap that won’t pop off until a force of 9.8 N is applied. What total height of water in the long arm (left arm) will put the seal on the verge of popping?

**2. Relevant equations**

F = ρ*V*g (Force = density * volume * acceleration from gravity)

**3. The attempt at a solution**

Trying to solve for the height h, I used the equation 9.8 N = (5.0 cm^{2})(1/10000 m^{2}/cm^{2})(h)(1 kg/m^{3})(9.81 m/s^{2})

I’m using the value 1 kg/m^{3} as the density of water and 9.81 m/s^{2} as the acceleration due to gravity.

Isolating h, I got 1998 m, which seems way to large. I must be doing something wrong. The units work out though. I end up with meters. But the number seems way too large.

http://ift.tt/1gdgwlZ

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