**1. The problem statement, all variables and given/known data**

A fox is 3.2 m from a 0.5 m tall wall. If it leaps from the ground towards the wall with an initial velocity of 12.0 m/s at angle of 18.9° above the horizontal, how high off the ground will the fox be when it reaches the wall?

**2. Relevant equations**

Δx = v_{x}t

Δy = 1/2a^{2}t

**3. The attempt at a solution**

First I tried to find Vy by doing "tan 18.9 = y/12"

and got 4.10 m/s.

Then I found the time by doing 3.2 = 12t

and got 0.266 sec.

I have no idea if I’m on the right track.

Then I just plugged in time and acceleration to find Δy and got 0.346 but it’s wrong.

The answer is supposed 0.7 m…

Any help?

http://ift.tt/PdV4pr