A fox is 3.2 m from a 0.5 m tall wall. If it leaps from the ground towards the wall with an initial velocity of 12.0 m/s at angle of 18.9° above the horizontal, how high off the ground will the fox be when it reaches the wall?
2. Relevant equations
Δx = vxt
Δy = 1/2a2t
3. The attempt at a solution
First I tried to find Vy by doing "tan 18.9 = y/12"
and got 4.10 m/s.
Then I found the time by doing 3.2 = 12t
and got 0.266 sec.
I have no idea if I’m on the right track.
Then I just plugged in time and acceleration to find Δy and got 0.346 but it’s wrong.
The answer is supposed 0.7 m…