# Archimedes Principle Problem: Floating Object

**1. The problem statement, all variables and given/known data**

A cylindrical log of uniform density and radius R=30.0cm floats so that the vertical distance from the water line to the top of the log is d = 12.0cm. What is the density of the log?

**2. Relevant equations**

F_{bouyant}=W_{waterdisplaced}

ρ_{water} * V _{displaced water} = ρ_{log} * V_{log}

**3. The attempt at a solution**

I started off by making a FBD. Buoyant force going up, mg coming down. No acceleration so I ended up getting to the second equation up above.

Solving for ρ_{log}, I get

ρ_{log} = ρ_{water} * (V_{displacedwater}/V_{log}) where V_{displacedwater} = ∏R^{2}

I’m having trouble figuring out the volume of the displaced water. Since only part of the log is submerged, would the volume of the displaced water be the volume of the log that is submerged? And if so, how I would go about determining the ratio of the volumes?

I tried several things already to no avail. I tried taking the ratio of the radius of the log to the distance to the top of level (.12/.30) and used the answer of .4 to use into the R of V_{displacewater} but didn’t get the answer.

I tried switching it and still got nothing. Some guidance in the right direction would be greatly appreciated. The answer is 858kg/m^{3}.

http://ift.tt/QGNple

## Leave a comment