A particle of mass m moves in a circle of
radius R at a constant speed v. Assume: The
motion begins from the point Q, which has
coordinates (R, 0).
Determine the angular momentum of the
particle about point P, which has coordinates
(−R, 0) as a function of time.
The answer choices can be found at: http://ift.tt/1jpDIBe
2. Relevant equations
v = Rω
L = R x p = Rpsin(θr,p) = Rmv(sinθr,p)
θf = θi + (ωit)
θf = θi + (vt/R)
3. The attempt at a solution
L1 at position Q = R x p = Rpsin(θr,p) = Rmv(sinθr,p)
L2 at position P = R x p
L2 at position P = Rpsin(-θr,p)
L2 at position P = Rmv(-sinθr,p)
L2 at position P = Rmv(sin((vt/R)+∏)))
However all answers have Rmv(____ + 1) factor. Which I do not have. Therefore I have reason to believe that my answer is incorrect.
My guess is that the answer is Rmv(sin((vt/R)+∏))+1)