On the x axis, charge +Q lies at x = -a and charge -Q lies at x = +a. Point P lies on the axis at
x = +b, where b > a. a) Work out the electric field magnitude of P b) What is the direction of this field?
2. Relevant equations
3. The attempt at a solution
E=2kQa/(b2-a2) + 2kQa/(b2-a2)=
Ep=4kQab/(b^2 – a^2)^2. My teacher said that the solution was correct, however my work was not.
For b, I determined the direction to be to the right towards the negative charge.
I would appreciate any assistance.