# Air pressure problem

I’m having trouble setting something up but here is what I do have;

Regarding liquids we know that F = (Rho)(height)(g) so I want to say that whatever "causes" the "air to push down" on the ground at 1 bar of pressure should have 500 meters worth of "height" removed from it. So force pushing down = 1 bar and (force pushing down) – 500 meters = answer.

So (Difference in force) = (density)(g)(height difference) where given density is in Kg/m^3, height is in m and g is m/s^2. Summing up these values we get Kg/m*s^2 Which is equal to a Newton. The atmospheric pressure is Newtons/m^2.

If I ignore this discrepancy (because the pressure is measuring F/A, and I’m solving just for the force) and solve to problem I end up with a huge number 1.3*8.9*500 which is obviously incorrect. Can someone please steer me in the right direction? thanks

http://ift.tt/1pXfJfa

## Leave a comment