At the instant of time calculate;
The velocity of bearing B.
The angular velocity of the link AB.
The acceleration of bearing B.
The angular acceleration of the link AB
2. velocity B = distance from rotational centre x angular velocity of link AB.
angular velocity of link AB = velocity A / distance from centre of zero velocity
3. from the working out in my picture changing it into a triangle I think I have worked out the velocity of bearing B and the angular velocity of link AB, but I dont know how to find the acceleration of B or the angular acceleration of AB.
Could somebody please help me with this and let me know if what i’ve done so far is incorrect?
3. The attempt at a solution
a = 0.05 c = 0.2
a2 + b2 = c2
0.22 / 0.052 = 16 root 16 = 4 b = 4
velocity A / distance from centre of zero velocity
0.1 / 0.05 = 2rad/s angular velocity of link AB
velocity B = distance from rotational centre(b) x angular velocity link AB
4 x 2 = 8m/s
ωv AB = 2rad/s
v B = 8m/s