# A stone is thrown vertically upward.

**1. The problem statement, all variables and given/known data**

A stone is thrown vertically upward. On its way up it passes point A with speed v, and point B, 3.00 m higher than A, with speed v/2. Calculate (a) the speed v and (b) the maximum height reached by the stone above the point B.

**2. Relevant equations**

Kinematic Equations

v = v(knot) + a(t)

V^2 = v(knot)^2 + 2a (x – x(knot))

x – x(knot) = v(knot)t + 0.5a(t)^2

**3. The attempt at a solution**

Because I’m not given time in the problem statement, I believe I start with Kinematic eq two. If I want to find speed at point A, I don’t know how to represent that as an x value. I know "a" is "-9.8" but am not given v(knot)^2. I’m left with too many variables.

Thank you.

http://ift.tt/1im3isy

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