A stone is thrown vertically upward. On its way up it passes point A with speed v, and point B, 3.00 m higher than A, with speed v/2. Calculate (a) the speed v and (b) the maximum height reached by the stone above the point B.
2. Relevant equations
v = v(knot) + a(t)
V^2 = v(knot)^2 + 2a (x – x(knot))
x – x(knot) = v(knot)t + 0.5a(t)^2
3. The attempt at a solution
Because I’m not given time in the problem statement, I believe I start with Kinematic eq two. If I want to find speed at point A, I don’t know how to represent that as an x value. I know "a" is "-9.8" but am not given v(knot)^2. I’m left with too many variables.