# A car is heading 43 m/s east. Find momentum, velocity.

Thanks in advance!

**1. The problem statement, all variables and given/known data**

A 1,988 kg car is moving at 43 m/s east. Suddenly, the driver slams on the brakes for 1.8 seconds, exerting a force of 6,000 N to the car.

A. What is the initial momentum of the car?

B. What is the change in momentum?

C. What is the final momentum of the car?

D. What is the final velocity of the car?

**2. Relevant equations**

a=f/m

v=v0+at

p=mv

**3. The attempt at a solution**

A. What is the initial momentum of the car?

p=mv

p=1988*43

p=85484 kg m/s

B. What is the change in momentum?

85484 kg m/s-74669 kg m/s=10815 kg m/s

C. What is the final momentum of the car?

p=1988*37.56 m/s

p=74669 kg m/s

D. What is the final velocity of the car?

a=f/m

a=6000/1988

a=-3.02 m/s^2

v=43+-3.02*1.8

v=37.56 m/s^2

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